ssis怎么用for循环生成连续的日期

0
比如从2009-01-01 00:00:00开始,一天一行数据,同时生成键值,有没有具体脚本示例
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壹酒捌捌 2014-09-25 回答

给你一个类似的存储过程:
CREATE PROCEDURE [dbo].[Create_time_by_day_dimension]

-- Add the parameters for the stored procedure here

AS

BEGIN

-- SET NOCOUNT ON added to prevent extra result sets from

-- interfering with SELECT statements.

SET NOCOUNT ON;

begin try

drop table [time_by_day_dimension]

end try

begin catch

end catch

CREATE TABLE [dbo].[time_by_day_dimension] (

[time_id] [int] IDENTITY (1, 1) NOT NULL ,

[the_date] [datetime] NULL ,

[the_day] [nvarchar] (15) NULL ,

[the_month] [nvarchar] (15) NULL ,

[the_year] [smallint] NULL ,

[day_of_month] [smallint] NULL ,

[week_of_year] [smallint] NULL ,

[month_of_year] [smallint] NULL ,

[quarter] [nvarchar] (2) NULL ,

[fiscal_period] [nvarchar] (20) NULL

) ON [PRIMARY]

DECLARE @WeekString varchar(12),

@dDate SMALLDATETIME,

@sMonth varchar(20),

@iYear smallint,

@iDayOfMonth smallint,

@iWeekOfYear smallint,

@iMonthOfYear smallint,

@sQuarter varchar(2),

@sSQL varchar(100),

@adddays int



SELECT @adddays = 1 --日期增量(可以自由设定)

SELECT @dDate = '01/01/2006' --开始日期



WHILE @dDate < '12/31/2010' --结束日期

BEGIN



SELECT @WeekString = DATENAME (dw, @dDate)

SELECT @sMonth=DATENAME(mm,@dDate)

SELECT @iYear= DATENAME (yy, @dDate)

SELECT @iDayOfMonth=DATENAME (dd, @dDate)

SELECT @iWeekOfYear= DATENAME (week, @dDate)

SELECT @iMonthOfYear=DATEPART(month, @dDate)

SELECT @sQuarter = 'Q' + CAST(DATENAME (quarter, @dDate)as varchar(1))

INSERT INTO time_by_day_dimension(the_date, the_day, the_month, the_year,

day_of_month,

week_of_year, month_of_year, quarter) VALUES

(@dDate, @WeekString, @sMonth, @iYear, @iDayOfMonth, @iWeekOfYear,

@iMonthOfYear, @sQuarter)

SELECT @dDate = @dDate + @adddays

END

END

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