ssis怎么用for循环生成连续的日期
0
比如从2009-01-01 00:00:00开始,一天一行数据,同时生成键值,有没有具体脚本示例
没有找到相关结果
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1 个回复
壹酒捌捌 2014-09-25 回答
赞同来自: error
CREATE PROCEDURE [dbo].[Create_time_by_day_dimension]
-- Add the parameters for the stored procedure here
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
begin try
drop table [time_by_day_dimension]
end try
begin catch
end catch
CREATE TABLE [dbo].[time_by_day_dimension] (
[time_id] [int] IDENTITY (1, 1) NOT NULL ,
[the_date] [datetime] NULL ,
[the_day] [nvarchar] (15) NULL ,
[the_month] [nvarchar] (15) NULL ,
[the_year] [smallint] NULL ,
[day_of_month] [smallint] NULL ,
[week_of_year] [smallint] NULL ,
[month_of_year] [smallint] NULL ,
[quarter] [nvarchar] (2) NULL ,
[fiscal_period] [nvarchar] (20) NULL
) ON [PRIMARY]
DECLARE @WeekString varchar(12),
@dDate SMALLDATETIME,
@sMonth varchar(20),
@iYear smallint,
@iDayOfMonth smallint,
@iWeekOfYear smallint,
@iMonthOfYear smallint,
@sQuarter varchar(2),
@sSQL varchar(100),
@adddays int
SELECT @adddays = 1 --日期增量(可以自由设定)
SELECT @dDate = '01/01/2006' --开始日期
WHILE @dDate < '12/31/2010' --结束日期
BEGIN
SELECT @WeekString = DATENAME (dw, @dDate)
SELECT @sMonth=DATENAME(mm,@dDate)
SELECT @iYear= DATENAME (yy, @dDate)
SELECT @iDayOfMonth=DATENAME (dd, @dDate)
SELECT @iWeekOfYear= DATENAME (week, @dDate)
SELECT @iMonthOfYear=DATEPART(month, @dDate)
SELECT @sQuarter = 'Q' + CAST(DATENAME (quarter, @dDate)as varchar(1))
INSERT INTO time_by_day_dimension(the_date, the_day, the_month, the_year,
day_of_month,
week_of_year, month_of_year, quarter) VALUES
(@dDate, @WeekString, @sMonth, @iYear, @iDayOfMonth, @iWeekOfYear,
@iMonthOfYear, @sQuarter)
SELECT @dDate = @dDate + @adddays
END
END