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dj123jary 2016-09-13 回答
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dj123jary 2016-09-13 回答
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> x
Call:
lm(formula = y ~ x1 + x2 + x3 + x4 + x6 + x7, data = demo2)
Residuals:
1 2 3 4 5 6 7 8 9 10
-1487 -14796 27510 -6662 -2963 -12354 40600 -6314 -2835 -20699
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 2.887e+06 4.660e+05 6.195 0.00847 **
x1 -9.413e-01 2.567e-01 -3.667 0.03506 *
x2 -4.080e+03 1.987e+03 -2.053 0.13232
x3 -7.807e-01 2.533e-01 -3.082 0.05404 .
x4 -5.437e+03 1.745e+03 -3.116 0.05265 .
x6 -3.536e+03 1.587e+03 -2.228 0.11221
x7 -7.423e+03 1.155e+03 -6.425 0.00764 **
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 33210 on 3 degrees of freedom
Multiple R-squared: 0.9517, Adjusted R-squared: 0.8552
F-statistic: 9.861 on 6 and 3 DF, p-value: 0.04374
> x$coefficients[,3]
(Intercept) x1 x2 x3 x4 x6 x7
6.195459 -3.667356 -2.053483 -3.082340 -3.115513 -2.227920 -6.425064
> x$coefficients[,"t value"]
(Intercept) x1 x2 x3 x4 x6 x7
6.195459 -3.667356 -2.053483 -3.082340 -3.115513 -2.227920 -6.425064
>